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0=15x^2-7x-4
We move all terms to the left:
0-(15x^2-7x-4)=0
We add all the numbers together, and all the variables
-(15x^2-7x-4)=0
We get rid of parentheses
-15x^2+7x+4=0
a = -15; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·(-15)·4
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*-15}=\frac{-24}{-30} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*-15}=\frac{10}{-30} =-1/3 $
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